Help with staying warm while camping in 35 degrees F…?
I will be sleeping in my van, but don’t know the best way to stay nice and toasty throughout the night. Are there heaters that plug into the dash? Certain types of blankets?
Since 70% of heat loss is thru the head, make sure you sleep with a good headcover, a wool watch cap works fine. Sleep in thermal underwear, with heavy socks. Use a good sleeping bag rated for the temps you expect to encounter. As for heaters, a plug into the dash heater would drain your battery in less than an hour. Propane or other gas heaters are dangerous in enclosed spaces as they suck up the oxygen and put off toxic fumes. A proper wall heater installed with proper vents is an option, but very expensive. Heat packs from any camping outlet, placed in your sleeping bag will also keep you toasty, but your gonna fog up and ice up the inside of your windows with your breath during the night.
Check with camping world, or other camp supply stores to see what may be new on the market and safe to use.
determine the magnitude and direction of her resultant displacement between the base camp and the ranger’s tow?
a hiker walks 25.5 km from her base camp at 35 degrees south of east. on the second day she walks 41 km in a direction 65 degrees north of east, at which point she discovers a forest ranger’s tower.
First you have to break them down into x and y- components.
x-component of her walking 25.5km = 25.5 cos 35 degrees
x- component of her walking 41km = 41 cos 65 degrees
add them both together to get your resultant displacement’s x value.
20.9 + 17.3
Now for y- component
y- component of her walking 25.5 = 25.5 sin 35 degrees
= – 14.6 ( since it’s underneath the y-axis therefore is negative)
y- component of her walking 41 = 41 sin 65 degrees
Add the together
-14.6 + 37.2 = 22.6
Now to find the resultant displacement we need to use Pythagorean theorem.
Resultant displacement = sqrt(22.6^2 + 38.2^2)
Therfore, the resultant dispalcement is 44.4km
Now the degrees would be
tan-1 Θ = 22.6 / 38.2
Θ = 37 degrees
final answer would be:
44.4km [E 37 degrees N]
While camping does it really keep you warmer to strip down or dress lightly when sleeping in a sleeping bag?
My husband and I just started backpacking in the mountains and I bought a 10 degree bag. Both times I have froze and I blame it on following his advice to ‘strip down to the minimum amount of clothing and then my body heat would keep me warm.’ The only way I could get back to sleep after waking up cold was to put on a sweatshirt and sweats so I think his theory is wrong. I don’t think its because my sleeping bag is inadequate because it maybe got down to only 35 degrees when we were camping. If you know the solution to staying warm when sleeping in the mountains please let me know. If you also know of any studies done please include websites so I have proof for my husband.
I had some of my own ideas but many of them and more are covered in the sites below.
If I believe I am going to get cold, I always have a stocking cap to put on because that is where you loose your heat. I wear at least 1 full thin layer; long john’s or sweats, long sleeved t-shirt. I keep another layer in my bag to put on just in case. I think the idea of having minimal clothes is not to sweat, then get chilled and also to not fill all the airspace up in the bag.
Don’t cover your head with the sleeping bag if you get cold because your breath holds a lot of moisture that will chill you in the long run.
Oh yeah…sometimes I will do jumping jacks or run in place just before I get in my bag to create body warmth. This helps a lot. (don’t get sweaty)
Sorry the only documentation I have is Many, many years of camping and some winter camping.
God luck and try to stay warm!!
What is the magnitude of displacement?
The summit of a mountain, 2700m above base camp, is measured on a map to be 4680m horizontally from the camp in a direction 35.4 degrees west of north. Choose the x axis east, y axis north, and z axis up.
Components of the displacement vector
What is its magnitude?
Can you show me how to work this out, please?
Two ways to do this
1) R = sqrt(Rx^2 +Ry^2 +Rz^2)
R = sqrt((-2710)^2 +3810^2 +2700^2) = 5399 m
2) R = sqrt(Rr^2 +Rz^2)
R = sqrt( 4680^2 +2700^2) =5403
This is just the pythagorean theorem in three dimensions
The difference in the results is round off error.
Powered by Yahoo! Answers